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Consider the Second-Order Differential Equation x27x(x+1)5x2 x^{2} \cdot \frac{7 x(x+1)}{5 x^{2}}

Question 53

Multiple Choice

Consider the second-order differential equation:  Consider the second-order differential equation:   . Why is C<sub>0</sub> = 0 a regular singular point? A)  The functions   x^{2} \cdot \frac{7 x(x+1) }{5 x^{2}}   and   x \cdot\left(-\frac{7}{5 x^{2}}\right)    both have convergent Taylor series expansions about 0 . B)  The functions   x \cdot \frac{7 x(x+1) }{5 x^{2}}   and   x^{2} \cdot\left(-\frac{7}{5 x^{2}}\right)    both have convergent Taylor series expansions about 0 . C)    \lim _{x \rightarrow 0} x \cdot\left(-\frac{7}{5 x^{2}}\right) =\infty   D)    \lim _{x \rightarrow 0} x \cdot\left(-\frac{7}{5 x^{2}}\right)  \neq 0 .
Why is C0 = 0 a regular singular point?


A) The functions x27x(x+1) 5x2 x^{2} \cdot \frac{7 x(x+1) }{5 x^{2}} and x(75x2) x \cdot\left(-\frac{7}{5 x^{2}}\right) both have convergent Taylor series expansions about 0 .
B) The functions x7x(x+1) 5x2 x \cdot \frac{7 x(x+1) }{5 x^{2}} and x2(75x2) x^{2} \cdot\left(-\frac{7}{5 x^{2}}\right) both have convergent Taylor series expansions about 0 .
C) limx0x(75x2) = \lim _{x \rightarrow 0} x \cdot\left(-\frac{7}{5 x^{2}}\right) =\infty
D) limx0x(75x2) 0 \lim _{x \rightarrow 0} x \cdot\left(-\frac{7}{5 x^{2}}\right) \neq 0

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