Solved

Solve
- F=95C+32F=\frac{9}{5} C+32 For CC A) C=5F−32C=\frac{5}{F-32} B) C=59(F−32)C=\frac{5}{9}(F-32) C) C=95(F−32)C=\frac{9}{5}(F-32) D) C=F−329\mathrm{C}=\frac{\mathrm{F}-32}{9}

Question 256

Multiple Choice

Solve.
- F=95C+32F=\frac{9}{5} C+32 for CC


A) C=5F−32C=\frac{5}{F-32}
B) C=59(F−32) C=\frac{5}{9}(F-32)
C) C=95(F−32) C=\frac{9}{5}(F-32)
D) C=F−329\mathrm{C}=\frac{\mathrm{F}-32}{9}

Correct Answer:

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