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  2. Topic
    Mathematics
  3. Study Set
    Introductory Algebra
  4. Exam
    Exam 2: Solving Equations and Inequalities
  5. Question
    Solve Using the Multiplication Principle\(-3 x<-9\) A)\(\{x \mid x>3\}\) B)\(\{x \mid x<-3\}\)
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Solve Using the Multiplication Principle −3x<−9-3 x<-9−3x<−9 A) {x∣x>3}\{x \mid x>3\}{x∣x>3} B) {x∣x<−3}\{x \mid x<-3\}{x∣x<−3}

Question 177

Question 177

Multiple Choice

Solve using the multiplication principle.
- −3x<−9-3 x<-9−3x<−9


A) {x∣x>3}\{x \mid x>3\}{x∣x>3}
B) {x∣x<−3}\{x \mid x<-3\}{x∣x<−3}
C) {x∣x<3}\{x \mid x<3\}{x∣x<3}
D) {x∣x>−3}\{x \mid x>-3\}{x∣x>−3}

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