Solve the Problem $54 \mathrm{~m}$ If the Width Were Doubled and the Length Were

Multiple Choice

Solve the problem.
-The perimeter of a rectangle is $54 \mathrm{~m}$ . If the width were doubled and the length were increased by $17 \mathrm{~m}$ , the perimeter would be $104 \mathrm{~m}$ . What are the length and width of the rectangle?

A) width $8 \mathrm{~m}$ , length $13 \mathrm{~m}$
B) width $8 \mathrm{~m}$ , length $19 \mathrm{~m}$
C) width $19 \mathrm{~m}$ , length $8 \mathrm{~m}$
D) width $13 \mathrm{~m}$ , length $13 \mathrm{~m}$