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    Mathematics
  3. Study Set
    Introductory Algebra
  4. Exam
    Exam 8: Radical Expressions and Equations
  5. Question
    Provide an Appropriate Response\(\sqrt{\mathrm{x}^{2}-36}=\sqrt{\mathrm{x}^{2}}-\sqrt{36}=\mathrm{x}-6\)
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Provide an Appropriate Response x2−36=x2−36=x−6\sqrt{\mathrm{x}^{2}-36}=\sqrt{\mathrm{x}^{2}}-\sqrt{36}=\mathrm{x}-6x2−36​=x2​−36​=x−6

Question 96

Question 96

Essay

Provide an appropriate response.
-Explain the error in the following: x2−36=x2−36=x−6\sqrt{\mathrm{x}^{2}-36}=\sqrt{\mathrm{x}^{2}}-\sqrt{36}=\mathrm{x}-6x2−36​=x2​−36​=x−6 .

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