Essay
A chocolate, caramel pecan piece of candy contains 115 food Calories (Cal). A food Calorie is equivalent to 1000 calories of heat energy. If the heat energy contained in the piece of candy were transferred to 53.5 kg of water at 25.0 °C, what would be the final temperature of the water? The specific heat of water is 4.18 J/g °C.
Correct Answer:
Verified
115 Cal × 
× = 4.8070 × 105 J (calc) = 4...View Answer
Unlock this answer now
Get Access to more Verified Answers free of charge
Correct Answer:
Verified
× = 4.8070 × 105 J (calc) = 4...View Answer
Unlock this answer now
Get Access to more Verified Answers free of charge
Q22: How many Joules of heat must be
Q23: The normal boiling point of a substance
Q24: What is the heat capacity of 84.0
Q25: If liquid methyl amine and hydrofluoric acid
Q26: The anomalously high boiling point of water
Q28: Which of the following molecules are capable
Q29: Which of the following is not a
Q30: What would be the temperature change, in
Q31: The calculation below is set up to
Q32: Which one of the following is classified