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$\frac{47}{188}=\frac{9}{n}$ A) $\{36\}$ B) $\{1645\}$ C) $\left\{\frac{1}{36}\right\}$ D) $\left\{\frac{423}{188}\right\}$

Question 181

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$\frac{47}{188}=\frac{9}{n}$

A) $\{36\}$

B) $\{1645\}$

C) $\left\{\frac{1}{36}\right\}$

D) $\left\{\frac{423}{188}\right\}$

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47188=9n\frac{47}{188}=\frac{9}{n}18847​=n9​ A) {36}\{36\}{36} B) {1645}\{1645\}{1645} C) {136}\left\{\frac{1}{36}\right\}{361​} D) {423188}\left\{\frac{423}{188}\right\}{188423​}

Multiple Choice

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$\frac{47}{188}=\frac{9}{n}$ A) $\{36\}$ B) $\{1645\}$ C) $\left\{\frac{1}{36}\right\}$ D) $\left\{\frac{423}{188}\right\}$

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