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4n29=n5\frac{4 n-2}{9}=\frac{n}{5} A) {45}\left\{\frac{4}{5}\right\} B) {511}\left\{\frac{5}{11}\right\} C) {1110}\left\{\frac{11}{10}\right\} D) {1011}\left\{\frac{10}{11}\right\}

Question 33

Multiple Choice

4n29=n5\frac{4 n-2}{9}=\frac{n}{5}


A) {45}\left\{\frac{4}{5}\right\}

B) {511}\left\{\frac{5}{11}\right\}

C) {1110}\left\{\frac{11}{10}\right\}

D) {1011}\left\{\frac{10}{11}\right\}

Correct Answer:

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