Solve the Inequality $|8 x-4|-3<-10$ A) $\left(-\frac{3}{8}, \infty\right)$ B) $\left(-\infty,-\frac{3}{8}\right) \cup\left(\frac{11}{8}, \infty\right)$ C) $\left(-\frac{3}{8}, \frac{11}{8}\right)$

Multiple Choice

Solve the inequality. Graph your solution on a number line, and write your solution in interval notation
- $|8 x-4|-3<-10$

A) $\left(-\frac{3}{8}, \infty\right)$

B) $\left(-\infty,-\frac{3}{8}\right) \cup\left(\frac{11}{8}, \infty\right)$

C) $\left(-\frac{3}{8}, \frac{11}{8}\right)$

D) $\varnothing$