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A Student Was Asked to Find Ordered Pairs That Solve X+2y=32x+4y=6\begin{gathered}X+2 y=3 \\2 x+4 y=6\end{gathered}

Question 199

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A student was asked to find ordered pairs that solve the system of equations
X+2y=32x+4y=6\begin{gathered}X+2 y=3 \\2 x+4 y=6\end{gathered}
The student claims that (1,1)(1,1) and (1,2)(-1,2) are the only solutions. Is the student correct?

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