$(\mathrm{x}+4)\left(\mathrm{x}^{2}-\mathrm{x}+7\right)$ A)$x^{3}+5 x^{2}+11 x+28$ B)$x^{3}+3 x^{2}+3 x+28$ C)$x^{3}+28$ D)$x^{3}+3 x^{2}+28$

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The Answer of $(\mathrm{x}+4)\left(\mathrm{x}^{2}-\mathrm{x}+7\right)$ A)$x^{3}+5 x^{2}+11 x+28$ B)$x^{3}+3 x^{2}+3 x+28$ C)$x^{3}+28$ D)$x^{3}+3 x^{2}+28$

$(\mathrm{x}+4)\left(\mathrm{x}^{2}-\mathrm{x}+7\right)$ A) $x^{3}+5 x^{2}+11 x+28$ B) $x^{3}+3 x^{2}+3 x+28$ C) $x^{3}+28$ D) $x^{3}+3 x^{2}+28$

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(x+4)(x2−x+7)(\mathrm{x}+4)\left(\mathrm{x}^{2}-\mathrm{x}+7\right)(x+4)(x2−x+7) A) x3+5x2+11x+28x^{3}+5 x^{2}+11 x+28x3+5x2+11x+28 B) x3+3x2+3x+28x^{3}+3 x^{2}+3 x+28x3+3x2+3x+28 C) x3+28x^{3}+28x3+28 D) x3+3x2+28x^{3}+3 x^{2}+28x3+3x2+28

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$(\mathrm{x}+4)\left(\mathrm{x}^{2}-\mathrm{x}+7\right)$ A) $x^{3}+5 x^{2}+11 x+28$ B) $x^{3}+3 x^{2}+3 x+28$ C) $x^{3}+28$ D) $x^{3}+3 x^{2}+28$

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