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Factor Completely $8 p^{3}-1$ A) $(8 p-1)\left(p^{2}+2 p+1\right)$ B) $(2 p-1)\left(4 p^{2}+1\right)$ C) $(2 p-1)\left(4 p^{2}+2 p+1\right)$

Question 133

Multiple Choice

Factor completely. If the polynomial cannot be factored, write "prime."
- $8 p^{3}-1$

A) $(8 p-1) \left(p^{2}+2 p+1\right)$
B) $(2 p-1) \left(4 p^{2}+1\right)$
C) $(2 p-1) \left(4 p^{2}+2 p+1\right)$
D) $(2 p+1) \left(4 p^{2}-2 p+1\right)$

Factor Completely 8p3−18 p^{3}-18p3−1 A) (8p−1)(p2+2p+1)(8 p-1)\left(p^{2}+2 p+1\right)(8p−1)(p2+2p+1) B) (2p−1)(4p2+1)(2 p-1)\left(4 p^{2}+1\right)(2p−1)(4p2+1) C) (2p−1)(4p2+2p+1)(2 p-1)\left(4 p^{2}+2 p+1\right)(2p−1)(4p2+2p+1)

Multiple Choice

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Factor Completely $8 p^{3}-1$ A) $(8 p-1)\left(p^{2}+2 p+1\right)$ B) $(2 p-1)\left(4 p^{2}+1\right)$ C) $(2 p-1)\left(4 p^{2}+2 p+1\right)$

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