Factor Completely$x^{3}+27$ A)$(x+3)\left(x^{2}-3 x+9\right)$ B)$(x-27)\left(x^{2}-1\right)$ C)$(x+3)\left(x^{2}+9\right)$ D)$(x-3)\left(x^{2}+3 x+9\right)$

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The Answer of Factor Completely$x^{3}+27$ A)$(x+3)\left(x^{2}-3 x+9\right)$ B)$(x-27)\left(x^{2}-1\right)$ C)$(x+3)\left(x^{2}+9\right)$ D)$(x-3)\left(x^{2}+3 x+9\right)$

Factor Completely $x^{3}+27$ A) $(x+3)\left(x^{2}-3 x+9\right)$ B) $(x-27)\left(x^{2}-1\right)$ C) $(x+3)\left(x^{2}+9\right)$ D) $(x-3)\left(x^{2}+3 x+9\right)$

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Factor Completely x3+27x^{3}+27x3+27 A) (x+3)(x2−3x+9)(x+3)\left(x^{2}-3 x+9\right)(x+3)(x2−3x+9) B) (x−27)(x2−1)(x-27)\left(x^{2}-1\right)(x−27)(x2−1) C) (x+3)(x2+9)(x+3)\left(x^{2}+9\right)(x+3)(x2+9) D) (x−3)(x2+3x+9)(x-3)\left(x^{2}+3 x+9\right)(x−3)(x2+3x+9)

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Factor Completely $x^{3}+27$ A) $(x+3)\left(x^{2}-3 x+9\right)$ B) $(x-27)\left(x^{2}-1\right)$ C) $(x+3)\left(x^{2}+9\right)$ D) $(x-3)\left(x^{2}+3 x+9\right)$

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