$\frac{2}{3} x^{2}-\frac{17}{6} x-\frac{5}{2}=0$ A)$\left\{-\frac{3}{4}, 5\right\}$ B)$\left\{-\frac{3}{4}\right\}$ C)$\left\{\frac{3}{4},-5\right\}$ D)$\{5\}$

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The Answer of $\frac{2}{3} x^{2}-\frac{17}{6} x-\frac{5}{2}=0$ A)$\left\{-\frac{3}{4}, 5\right\}$ B)$\left\{-\frac{3}{4}\right\}$ C)$\left\{\frac{3}{4},-5\right\}$ D)$\{5\}$

$\frac{2}{3} x^{2}-\frac{17}{6} x-\frac{5}{2}=0$ A) $\left\{-\frac{3}{4}, 5\right\}$ B) $\left\{-\frac{3}{4}\right\}$ C) $\left\{\frac{3}{4},-5\right\}$ D) $\{5\}$

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23x2−176x−52=0\frac{2}{3} x^{2}-\frac{17}{6} x-\frac{5}{2}=032​x2−617​x−25​=0 A) {−34,5}\left\{-\frac{3}{4}, 5\right\}{−43​,5} B) {−34}\left\{-\frac{3}{4}\right\}{−43​} C) {34,−5}\left\{\frac{3}{4},-5\right\}{43​,−5} D) {5}\{5\}{5}

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$\frac{2}{3} x^{2}-\frac{17}{6} x-\frac{5}{2}=0$ A) $\left\{-\frac{3}{4}, 5\right\}$ B) $\left\{-\frac{3}{4}\right\}$ C) $\left\{\frac{3}{4},-5\right\}$ D) $\{5\}$

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