For the Given Quadratic Equation, One of Its Solutions Has $15 x^{2}+29 x+12=0, x=-\frac{4}{3}$

Multiple Choice

For the given quadratic equation, one of its solutions has been provided. Use it to find the other solution.
- $15 x^{2}+29 x+12=0, x=-\frac{4}{3}$

A) $x=\frac{4}{3}$

B) $x=-\frac{5}{3}$

C) $x=-\frac{3}{5}$

D) $x=\frac{3}{5}$