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4x+8x−3⋅2x2−12x+18x2−4\frac{4 x+8}{x-3} \cdot \frac{2 x^{2}-12 x+18}{x^{2}-4} A) 8(x+2)(x−3)x2−4\frac{8(x+2)(x-3)}{x^{2}-4} B) 4(x−3)x−2\frac{4(x-3)}{x-2} C) 8(x−3)x−2\frac{8(x-3)}{x-2} D) 8(x−3)x+2\frac{8(x-3)}{x+2}

Question 79

Multiple Choice

4x+8x−3⋅2x2−12x+18x2−4\frac{4 x+8}{x-3} \cdot \frac{2 x^{2}-12 x+18}{x^{2}-4}


A) 8(x+2) (x−3) x2−4\frac{8(x+2) (x-3) }{x^{2}-4}

B) 4(x−3) x−2\frac{4(x-3) }{x-2}

C) 8(x−3) x−2\frac{8(x-3) }{x-2}

D) 8(x−3) x+2\frac{8(x-3) }{x+2}

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