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Find the Missing Numerator and Denominator x+4x−7⋅??=(x+4)(x−1)(x−7)(x+3)\frac{x+4}{x-7} \cdot \frac{?}{?}=\frac{(x+4)(x-1)}{(x-7)(x+3)} A) x−1x+3\frac{x-1}{x+3} B) x(x−1)x(x+3)\frac{x(x-1)}{x(x+3)}

Question 6

Multiple Choice

Find the missing numerator and denominator.
- x+4x−7⋅??=(x+4) (x−1) (x−7) (x+3) \frac{x+4}{x-7} \cdot \frac{?}{?}=\frac{(x+4) (x-1) }{(x-7) (x+3) }


A) x−1x+3\frac{x-1}{x+3}

B) x(x−1) x(x+3) \frac{x(x-1) }{x(x+3) }

C) x+1x−3\frac{x+1}{x-3}

D) x(4x−1) x(7x+3) \frac{x(4 x-1) }{x(7 x+3) }

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