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Find the Missing Numerator and Denominator x2−1x2+6x+9÷??=(x+1)(x−5)5(x+3)\frac{x^{2}-1}{x^{2}+6 x+9} \div \frac{?}{?}=\frac{(x+1)(x-5)}{5(x+3)} A) 5x+5x2−2x−15\frac{5 x+5}{x^{2}-2 x-15}

Question 41

Multiple Choice

Find the missing numerator and denominator.
- x2−1x2+6x+9÷??=(x+1) (x−5) 5(x+3) \frac{x^{2}-1}{x^{2}+6 x+9} \div \frac{?}{?}=\frac{(x+1) (x-5) }{5(x+3) }


A) 5x+5x2−2x−15\frac{5 x+5}{x^{2}-2 x-15}

B) x+3(x+1) (x−5) \frac{x+3}{(x+1) (x-5) }

C) (x+1) (x−5) x+3\frac{(x+1) (x-5) }{x+3}

D) 5x−5x2−2x−15\frac{5 x-5}{x^{2}-2 x-15}

Correct Answer:

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