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Newton's Law of Universal Gravitation Relates the Force FF With Which a Particle of Mass

Question 49

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Newton's Law of universal gravitation relates the force FF with which a particle of mass m1m_{1} attracts a particle of mass m2\mathrm{m}_{2} to the gravitational constant G\mathrm{G} and the distance rr between the two objects: F=Gm1 m2r2\mathrm{F}=\frac{\mathrm{Gm} 1 \mathrm{~m} 2}{\mathrm{r}^{2}} . Solve this equation for G\mathrm{G} .


A) G=Fr2 m1 m2\mathrm{G}=\frac{\mathrm{Fr}^{2}}{\mathrm{~m}_{1} \mathrm{~m}_{2}}

B) G=r2m1Fm2G=\frac{r^{2} m_{1}}{F m 2}

C) G=Fm1r2 m2\mathrm{G}=\frac{\mathrm{Fm} 1}{\mathrm{r}^{2} \mathrm{~m}_{2}}

D) G=m1 m2Fr2\mathrm{G}=\frac{\mathrm{m}_{1} \mathrm{~m}_{2}}{\mathrm{Fr}^{2}}

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