The Length of the Diagonal of a Rectangle Is Given $D=\sqrt{L^{2}+W^{2}}$

Multiple Choice

The length of the diagonal of a rectangle is given by $D=\sqrt{L^{2}+W^{2}}$ where $L$ and $W$ are the length and width of the rectangle. What is the length of the diagonal, D, of a rectangle that is 16 inches long and 2 inches wide? Round your answer to the nearest tenth of an inch, if necessary.

A) 15.9 inches
B) 5.7 inches
C) 4.2 inches
D) 16.1 inches