The Length a Spring Is Stretched from Its Natural Length $\mathrm{L}=\sqrt{\frac{2 \mathrm{~W}}{\mathrm{k}}}$

Multiple Choice

The length a spring is stretched from its natural length with work, W foot- pounds, is given by $\mathrm{L}=\sqrt{\frac{2 \mathrm{~W}}{\mathrm{k}}}$
Where $\mathrm{k}$ is a constant for the given spring. If a certain spring has a constant of 65.7, and the spring is to be stretched 2.6 feet from its natural length, how much work will be necessary? Round to the nearest tenth of a foot- pound.

A) 222.1 foot- pounds
B) 53 foot- pounds
C) 444.1 foot- pounds
D) 85.4 foot- pounds