The Length of the Diagonal of a Box Is Given $D=\sqrt{\mathrm{L}^{2}+\mathrm{W}^{2}+\mathrm{H}^{2}}$

Multiple Choice

The length of the diagonal of a box is given by $D=\sqrt{\mathrm{L}^{2}+\mathrm{W}^{2}+\mathrm{H}^{2}}$ where $\mathrm{L}, \mathrm{W}$ , and $\mathrm{H}$ are the length, width, and height of the box. Find the length of the diagonal, D, of a box that is $2 \mathrm{ft}$ long, $2 \mathrm{ft}$ high, and $4 \mathrm{ft}$ wide. Give the exact value.

A) $8 \mathrm{ft}$
B) $2 \sqrt{6} \mathrm{ft}$
C) $16 \mathrm{ft}$
D) $4 \mathrm{ft}$