Rewrite in Exponential Form$\log _{5} \frac{1}{25}=-2$ A)$\left(\frac{1}{25}\right)^{2}=5$ B)$5^{25}=2$ C)$5^{-2}=\frac{1}{25}$ D)$2^{5}=\frac{1}{25}$

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The Answer of Rewrite in Exponential Form$\log _{5} \frac{1}{25}=-2$ A)$\left(\frac{1}{25}\right)^{2}=5$ B)$5^{25}=2$ C)$5^{-2}=\frac{1}{25}$ D)$2^{5}=\frac{1}{25}$

Rewrite in Exponential Form $\log _{5} \frac{1}{25}=-2$ A) $\left(\frac{1}{25}\right)^{2}=5$ B) $5^{25}=2$ C) $5^{-2}=\frac{1}{25}$ D) $2^{5}=\frac{1}{25}$

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Rewrite in Exponential Form log⁡5125=−2\log _{5} \frac{1}{25}=-2log5​251​=−2 A) (125)2=5\left(\frac{1}{25}\right)^{2}=5(251​)2=5 B) 525=25^{25}=2525=2 C) 5−2=1255^{-2}=\frac{1}{25}5−2=251​ D) 25=1252^{5}=\frac{1}{25}25=251​

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Rewrite in Exponential Form $\log _{5} \frac{1}{25}=-2$ A) $\left(\frac{1}{25}\right)^{2}=5$ B) $5^{25}=2$ C) $5^{-2}=\frac{1}{25}$ D) $2^{5}=\frac{1}{25}$

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