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Solve the Equation log7(6x1)+log7x=1\log _{7}(6 x-1)+\log _{7} \mathrm{x}=1 A) {76}\left\{\frac{7}{6}\right\} B) \varnothing C) {1,76}\left\{-1, \frac{7}{6}\right\}

Question 308

Multiple Choice

Solve the equation.
- log7(6x1) +log7x=1\log _{7}(6 x-1) +\log _{7} \mathrm{x}=1


A) {76}\left\{\frac{7}{6}\right\}
B) \varnothing
C) {1,76}\left\{-1, \frac{7}{6}\right\}
D) {1}\{-1\}

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