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Solve the Equation logx+log(x+1)=log2\log x+\log (x+1)=\log 2 A) {32}\left\{\frac{3}{2}\right\} B) {1,2}\{-1,2\} C) {2}\{2\} D) {1}\{1\}

Question 397

Multiple Choice

Solve the equation.
- logx+log(x+1) =log2\log x+\log (x+1) =\log 2


A) {32}\left\{\frac{3}{2}\right\}
B) {1,2}\{-1,2\}
C) {2}\{2\}
D) {1}\{1\}

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