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Determine the Equation of the Vertical Asymptote for the Graph f(x)=log(2x+1)+12f(x)=\log (2 x+1)+12

Question 23

Multiple Choice

Determine the equation of the vertical asymptote for the graph of this function, and state the domain and range of this function.
- f(x) =log(2x+1) +12f(x) =\log (2 x+1) +12


A) Vertical asymptote: x=12x=-\frac{1}{2} ;
Domain: (12,) \left(-\frac{1}{2}, \infty\right) , Range: (,) (-\infty, \infty)
B) Vertical asymptote: x=2\mathrm{x}=-2 ;
Domain: (2,) (-2, \infty) , Range: (,) (-\infty, \infty)
C) Vertical asymptote: x=12x=\frac{1}{2} ;
Domain: (12,) \left(\frac{1}{2}, \infty\right) , Range: (,) (-\infty, \infty)
D) Vertical asymptote: x=12\mathrm{x}=-12 ;
Domain: (12,) (-12, \infty) , Range: (,) (-\infty, \infty)

Correct Answer:

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