Solved

Solve the Problem $x^{2}+(y-140)^{2}=19,600$ B) $\mathrm{x}^{2}+\mathrm{y}^{2}=19,600$ C) $x^{2}+(y-140)^{2}=78,400$ D) $x^{2}+(y-152)^{2}=19,600$

Question 11

Multiple Choice

Solve the problem.
-A Ferris wheel has a diameter of 280 feet and the bottom of the Ferris wheel is 12 feet above the ground. Find the equation of the wheel if the origin is placed on the ground directly below the center of the wheel, as illustrated.
$Solve the problem. -A Ferris wheel has a diameter of 280 feet and the bottom of the Ferris wheel is 12 feet above the ground. Find the equation of the wheel if the origin is placed on the ground directly below the center of the wheel, as illustrated. A) x^{2}+(y-140) ^{2}=19,600 B) \mathrm{x}^{2}+\mathrm{y}^{2}=19,600 C) x^{2}+(y-140) ^{2}=78,400 D) x^{2}+(y-152) ^{2}=19,600$

A) $x^{2}+(y-140) ^{2}=19,600$
B) $\mathrm{x}^{2}+\mathrm{y}^{2}=19,600$
C) $x^{2}+(y-140) ^{2}=78,400$
D) $x^{2}+(y-152) ^{2}=19,600$

Solve the Problem x2+(y−140)2=19,600x^{2}+(y-140)^{2}=19,600x2+(y−140)2=19,600 B) x2+y2=19,600\mathrm{x}^{2}+\mathrm{y}^{2}=19,600x2+y2=19,600 C) x2+(y−140)2=78,400x^{2}+(y-140)^{2}=78,400x2+(y−140)2=78,400 D) x2+(y−152)2=19,600x^{2}+(y-152)^{2}=19,600x2+(y−152)2=19,600

Multiple Choice

Correct Answer:VerifiedUnlock this answer nowGet Access to more Verified Answers free of chargeAccess For Free

Solve the Problem $x^{2}+(y-140)^{2}=19,600$ B) $\mathrm{x}^{2}+\mathrm{y}^{2}=19,600$ C) $x^{2}+(y-140)^{2}=78,400$ D) $x^{2}+(y-152)^{2}=19,600$

Correct Answer:
Verified
Unlock this answer now
Get Access to more Verified Answers free of charge