Solved

For f(x)=x2−3x+4f(x)=x^{2}-3 x+4 , What Is f(1x−2)f\left(\frac{1}{x-2}\right) ?
A) 4x2−19x+23x2−4x+4\frac{4 x^{2}-19 x+23}{x^{2}-4 x+4}

Question 44

Multiple Choice

For f(x) =x2−3x+4f(x) =x^{2}-3 x+4 , what is f(1x−2) f\left(\frac{1}{x-2}\right) ?


A) 4x2−19x+23x2−4x+4\frac{4 x^{2}-19 x+23}{x^{2}-4 x+4}
B) 4x2−19x−9x2−4x+4\frac{4 x^{2}-19 x-9}{x^{2}-4 x+4}
C) 4x2−13x−9x2−4x+4\frac{4 x^{2}-13 x-9}{x^{2}-4 x+4}
D) 4x2−13x+11x2−4x+4\frac{4 x^{2}-13 x+11}{x^{2}-4 x+4}

Correct Answer:

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