Suppose $g(x)=\frac{1-11 x}{3}$ And Suppose That $f$ Is an Invertible Function Such That

Short Answer

Suppose $g(x)=\frac{1-11 x}{3}$ and suppose that $f$ is an invertible function such that
$f^{-1}(x)=3(x-5)$ . Find $f(g(x))$ and
write it in the form $a x+b$ .