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Rewriting 103=100010^{3}=1000 Using Logs Gives
A) log⁡(1000)=−3 \log (1000)=-3 B) log⁡(3)=−1000\log (3)=-1000 C) log⁡(1000)=3 \log (1000)=3

Question 19

Multiple Choice

Rewriting 103=100010^{3}=1000 using logs gives


A) log⁡(1000) =−3 \log (1000) =-3
B) log⁡(3) =−1000\log (3) =-1000
C) log⁡(1000) =3 \log (1000) =3
D) log⁡(3) =1000\log (3) =1000

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