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Rewriting e6a=be^{6 a}=b Using Logs Gives
A) lna=b/6\ln a=b/6 B) ln(b/6)=a\ln (b / 6)=a

Question 70

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Rewriting e6a=be^{6 a}=b using logs gives


A) lna=b/6\ln a=b/6
B) ln(b/6) =a\ln (b / 6) =a
C) ln6a=b\ln 6 a=b
D) lnb=6a\ln b=6 a

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