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Does (cos⁡θ−sin⁡θ)2−(cos⁡θ+sin⁡θ)22sin⁡2θ=1\frac{(\cos \theta-\sin \theta)^{2}-(\cos \theta+\sin \theta)^{2}}{2 \sin 2 \theta}=1

Question 68

True/False

Does (cos⁡θ−sin⁡θ)2−(cos⁡θ+sin⁡θ)22sin⁡2θ=1\frac{(\cos \theta-\sin \theta)^{2}-(\cos \theta+\sin \theta)^{2}}{2 \sin 2 \theta}=1 ?

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