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If y=3x2+16x2=u(v(x))y=\frac{3 x^{2}+1}{6 x^{2}}=u(v(x)) , Which of the Following Could Be True? Mark All

Question 28

Multiple Choice

If y=3x2+16x2=u(v(x) ) y=\frac{3 x^{2}+1}{6 x^{2}}=u(v(x) ) , which of the following could be true? Mark all that apply.


A) u(x) =3x+16x,v(x) =x2u(x) =\frac{3 x+1}{6 x}, v(x) =x^{2}
B) u(x) =x2,v(x) =3x+16xu(x) =x^{2}, v(x) =\frac{3 x+1}{6 x}
C) u(x) =x2x2,v(x) =3x2+1 u(x) =\frac{x}{2 x-2}, v(x) =3 x^{2}+1
D) u(x) =x6x1,v(x) =3x2+1 u(x) =\frac{x}{6 x-1}, v(x) =3 x^{2}+1
E) u(x) =3x+1x,v(x) =6x2 u(x) =\frac{3 x+1}{x}, v(x) =6 x^{2}

Correct Answer:

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