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The Functions ff And FF Are Given By f(x)=kxpf(x)=k x^{p} And F(x)=kxp1pF(x)=\sqrt{\frac{k x^{p-1}}{p}}
Suppose

Question 55

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The functions ff and FF are given by f(x)=kxpf(x)=k x^{p} and F(x)=kxp1pF(x)=\sqrt{\frac{k x^{p-1}}{p}} .
Suppose f(x)=x98f(x)=\frac{x^{9}}{8} . What must FF be?

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