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The Volume of Pollutants (In Millions of Cubic Feet) in a Certain

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The volume of pollutants (in millions of cubic feet) in a certain reservoir is given by P(t)=370+25tP(t)=370+25 t , where tt is time in years. The volume of the reservoir (including pollutants) is gradually increasing and is given by R(t)=11,000+130tR(t)=11,000+130 t . Let C(t)C(t) be the fraction of the reservoir's volume that consists of pollutants. What percent of the reservoir's total volume consisted of pollutants in the year t=0t=0 ? Round to 1 decimal place.

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