Given That $\mathbf{A}=\left(\begin{array}{ccc}1 & 1 & 2 \\ 4 & -1 & -3 \\ 4 & 0 & 2\end{array}\right)$

Short Answer

Given that $\mathbf{A}=\left(\begin{array}{ccc}1 & 1 & 2 \\ 4 & -1 & -3 \\ 4 & 0 & 2\end{array}\right)$ and $\mathbf{B}=\left(\begin{array}{ccc}1 & 1 & -3 \\ 2 & -4 & 0 \\ -1 & -2 & 3\end{array}\right)$ , let $((\mathbf{A}-\mathbf{B})-\mathbf{B})-\mathbf{B}=\mathbf{C}$ ,
where $\mathbf{C}=\left(\begin{array}{lll}c_{11} & c_{12} & c_{13} \\ c_{21} & c_{22} & c_{23} \\ c_{31} & c_{32} & c_{33}\end{array}\right)$ . What is $c_{12}$ ?