If the Circle $x^{2}+y^{2}+14 x-6 y+9=0$ Is Converted to the Parametric Equations

Short Answer

If the circle $x^{2}+y^{2}+14 x-6 y+9=0$ is converted to the parametric equations $x=h+r \cos t, y=k+r \sin t, 0 \leq t \leq 2 \pi$ , then h=------------,k=----------,and r=------------.