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    Functions Modeling Change
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    Exam 14: Parametric Equations and Conic Sections
  5. Question
    What Is the Radius of the Circle\(5(x-5)^{2}+4(y+6)^{2}-45=-(y+6)^{2}\)
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What Is the Radius of the Circle 5(x−5)2+4(y+6)2−45=−(y+6)25(x-5)^{2}+4(y+6)^{2}-45=-(y+6)^{2}5(x−5)2+4(y+6)2−45=−(y+6)2

Question 80

Question 80

Short Answer

What is the radius of the circle 5(x−5)2+4(y+6)2−45=−(y+6)25(x-5)^{2}+4(y+6)^{2}-45=-(y+6)^{2}5(x−5)2+4(y+6)2−45=−(y+6)2 ?

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