Find the Upper Intersection Point of the Ellipse $\frac{(x+3)^{2}}{9}+\frac{(y-3)^{2}}{16}=1$ And the Line

Short Answer

Find the upper intersection point of the ellipse $\frac{(x+3)^{2}}{9}+\frac{(y-3)^{2}}{16}=1$ and the line $x=$ -2 . Round the $y$ -coordinate to 2 decimal points.