In the Hyperbola Given by the Equation$\frac{(x-6)^{2}}{49}-\frac{(y-4)^{2}}{25}=1$ , the Left Vertex Is at (-----------,-------------)

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The Answer of In the Hyperbola Given by the Equation$\frac{(x-6)^{2}}{49}-\frac{(y-4)^{2}}{25}=1$ , the Left Vertex Is at (-----------,-------------)

In the Hyperbola Given by the Equation $\frac{(x-6)^{2}}{49}-\frac{(y-4)^{2}}{25}=1$ , the Left Vertex Is at (-----------,-------------)