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What Is the Point of Intersection in the First Quadrant x2+y2=12x^{2}+y^{2}=\frac{1}{2}

Question 49

Short Answer

What is the point of intersection in the first quadrant of the curves x2+y2=12x^{2}+y^{2}=\frac{1}{2} and x2−y2=14?x^{2}-y^{2}=\frac{1}{4} ? Round each coordinate to 2 decimal places.

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