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Solve the Problem h+vt4.9t2\mathrm{h}+\mathrm{vt}-4.9 \mathrm{t}^{2} , Where h\mathrm{h} Is the Height in Meters from Which the Launch Occurs

Question 343

Multiple Choice

Solve the problem.
-An object's altitude, in meters, is given by the polynomial h+vt4.9t2\mathrm{h}+\mathrm{vt}-4.9 \mathrm{t}^{2} , where h\mathrm{h} is the height in meters from which the launch occurs, vv is the initial upward speed in meters per second, and tt is the number of seconds for which the rocket is airborne. A pebble is shot upward from the top of a building 171 meters tall. If the initial speed is 35 meters per second, how high above the ground will the pebble be after 3 seconds? Round results to the nearest tenth of a meter.


A) 261.3 meters
B) 320.1 meters
C) 231.9 meters
D) 503.9 meters

Correct Answer:

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