Factor Completely $4 \mathrm{k}^{2}-121 \mathrm{~m}^{2}$ A) $(4 k+m)(k-121 m)$ B) $(2 \mathrm{k}+11 \mathrm{~m})(2 \mathrm{k}-11 \mathrm{~m})$

Multiple Choice

Factor completely.
- $4 \mathrm{k}^{2}-121 \mathrm{~m}^{2}$

A) $(4 k+m) (k-121 m)$
B) $(2 \mathrm{k}+11 \mathrm{~m}) (2 \mathrm{k}-11 \mathrm{~m})$
C) $(2 k-11 m) ^{2}$
D) $(2 \mathrm{k}+11 \mathrm{~m}) ^{2}$