Solve Using the Principle of Zero Products$\left(5 x-\frac{1}{4}\right)\left(x+\frac{1}{5}\right)=0$ A)$-\frac{1}{20},-\frac{1}{5}$ B)$-\frac{1}{20}, \frac{1}{5}$

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The Answer of Solve Using the Principle of Zero Products$\left(5 x-\frac{1}{4}\right)\left(x+\frac{1}{5}\right)=0$ A)$-\frac{1}{20},-\frac{1}{5}$ B)$-\frac{1}{20}, \frac{1}{5}$

Solve Using the Principle of Zero Products $\left(5 x-\frac{1}{4}\right)\left(x+\frac{1}{5}\right)=0$ A) $-\frac{1}{20},-\frac{1}{5}$ B) $-\frac{1}{20}, \frac{1}{5}$

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Solve Using the Principle of Zero Products (5x−14)(x+15)=0\left(5 x-\frac{1}{4}\right)\left(x+\frac{1}{5}\right)=0(5x−41​)(x+51​)=0 A) −120,−15-\frac{1}{20},-\frac{1}{5}−201​,−51​ B) −120,15-\frac{1}{20}, \frac{1}{5}−201​,51​

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Solve Using the Principle of Zero Products $\left(5 x-\frac{1}{4}\right)\left(x+\frac{1}{5}\right)=0$ A) $-\frac{1}{20},-\frac{1}{5}$ B) $-\frac{1}{20}, \frac{1}{5}$

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