Solve the Problem $52 \mathrm{~m}$ If the Width Were Doubled and the Length Were

Multiple Choice

Solve the problem.
-The perimeter of a rectangle is $52 \mathrm{~m}$ . If the width were doubled and the length were increased by $24 \mathrm{~m}$ , the perimeter would be $114 \mathrm{~m}$ . What are the length and width of the rectangle?

A) width $13 \mathrm{~m}$ , length $13 \mathrm{~m}$
B) width $19 \mathrm{~m}$ , length $7 \mathrm{~m}$
C) width $7 \mathrm{~m}$ , length $19 \mathrm{~m}$
D) width $8 \mathrm{~m}$ , length $13 \mathrm{~m}$