Solve by Elimination $x-\frac{2}{3} y=\frac{89}{12}$ $\frac{2}{3} x+y=-\frac{19}{2}$ A) $\left(\frac{3}{4},-10\right)$ B) $\left(-10,-\frac{3}{4}\right)$ C) $\left(\frac{3}{4}, 10\right)$

Multiple Choice

Solve by elimination.
- $x-\frac{2}{3} y=\frac{89}{12}$
$\frac{2}{3} x+y=-\frac{19}{2}$

A) $\left(\frac{3}{4},-10\right)$
B) $\left(-10,-\frac{3}{4}\right)$
C) $\left(\frac{3}{4}, 10\right)$
D) $\left(10, \frac{3}{4}\right)$