Solve Clear Fractions First$x+\frac{4}{3}+\frac{9}{8} x=\frac{7}{2}+\frac{3}{4} x$ A)$\frac{52}{33}$ B)$\frac{59}{33}$ C)$\frac{4}{3}$ D)$\frac{56}{39}$

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The Answer of Solve Clear Fractions First$x+\frac{4}{3}+\frac{9}{8} x=\frac{7}{2}+\frac{3}{4} x$ A)$\frac{52}{33}$ B)$\frac{59}{33}$ C)$\frac{4}{3}$ D)$\frac{56}{39}$

Solve Clear Fractions First $x+\frac{4}{3}+\frac{9}{8} x=\frac{7}{2}+\frac{3}{4} x$ A) $\frac{52}{33}$ B) $\frac{59}{33}$ C) $\frac{4}{3}$ D) $\frac{56}{39}$

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Solve Clear Fractions First x+43+98x=72+34xx+\frac{4}{3}+\frac{9}{8} x=\frac{7}{2}+\frac{3}{4} xx+34​+89​x=27​+43​x A) 5233\frac{52}{33}3352​ B) 5933\frac{59}{33}3359​ C) 43\frac{4}{3}34​ D) 5639\frac{56}{39}3956​

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Solve Clear Fractions First $x+\frac{4}{3}+\frac{9}{8} x=\frac{7}{2}+\frac{3}{4} x$ A) $\frac{52}{33}$ B) $\frac{59}{33}$ C) $\frac{4}{3}$ D) $\frac{56}{39}$

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