Solved

Solve Using the Addition Principle $-12<-23$ A) $\{\mathrm{a} \mid \mathrm{a}<-11\}$ B) $\{\mathrm{a} \mid \mathrm{a} \geq-11\}$

Question 138

Multiple Choice

Solve using the addition principle. Graph and write set-builder notation for the answer.
-a $-12<-23$ $Solve using the addition principle. Graph and write set-builder notation for the answer. -a -12<-23 A) \{\mathrm{a} \mid \mathrm{a}<-11\} B) \{\mathrm{a} \mid \mathrm{a} \geq-11\} C) \{\mathrm{a} \mid \mathrm{a}>-11\} D) \{\mathrm{a} \mid \mathrm{a} \leq-11\}$

A) $\{\mathrm{a} \mid \mathrm{a}<-11\}$
$Solve using the addition principle. Graph and write set-builder notation for the answer. -a -12<-23 A) \{\mathrm{a} \mid \mathrm{a}<-11\} B) \{\mathrm{a} \mid \mathrm{a} \geq-11\} C) \{\mathrm{a} \mid \mathrm{a}>-11\} D) \{\mathrm{a} \mid \mathrm{a} \leq-11\}$
B) $\{\mathrm{a} \mid \mathrm{a} \geq-11\}$
$Solve using the addition principle. Graph and write set-builder notation for the answer. -a -12<-23 A) \{\mathrm{a} \mid \mathrm{a}<-11\} B) \{\mathrm{a} \mid \mathrm{a} \geq-11\} C) \{\mathrm{a} \mid \mathrm{a}>-11\} D) \{\mathrm{a} \mid \mathrm{a} \leq-11\}$
C) $\{\mathrm{a} \mid \mathrm{a}>-11\}$
$Solve using the addition principle. Graph and write set-builder notation for the answer. -a -12<-23 A) \{\mathrm{a} \mid \mathrm{a}<-11\} B) \{\mathrm{a} \mid \mathrm{a} \geq-11\} C) \{\mathrm{a} \mid \mathrm{a}>-11\} D) \{\mathrm{a} \mid \mathrm{a} \leq-11\}$
D) $\{\mathrm{a} \mid \mathrm{a} \leq-11\}$
$Solve using the addition principle. Graph and write set-builder notation for the answer. -a -12<-23 A) \{\mathrm{a} \mid \mathrm{a}<-11\} B) \{\mathrm{a} \mid \mathrm{a} \geq-11\} C) \{\mathrm{a} \mid \mathrm{a}>-11\} D) \{\mathrm{a} \mid \mathrm{a} \leq-11\}$

Solve Using the Addition Principle −12<−23-12<-23−12<−23 A) {a∣a<−11}\{\mathrm{a} \mid \mathrm{a}<-11\}{a∣a<−11} B) {a∣a≥−11}\{\mathrm{a} \mid \mathrm{a} \geq-11\}{a∣a≥−11}

Multiple Choice

Correct Answer:VerifiedUnlock this answer nowGet Access to more Verified Answers free of chargeAccess For Free

Solve Using the Addition Principle $-12<-23$ A) $\{\mathrm{a} \mid \mathrm{a}<-11\}$ B) $\{\mathrm{a} \mid \mathrm{a} \geq-11\}$

Correct Answer:
Verified
Unlock this answer now
Get Access to more Verified Answers free of charge