Solved

Solve Using the Addition Principle $x+\frac{1}{7}>\frac{4}{7}$ A) $\left\{|x| x>-\frac{3}{7}\right\}$ B) $\left\{|x| x>\frac{3}{7}\right\}$ C) $\left\{\left\{x \mid x<\frac{4}{7}\right\}\right.$

Question 204

Multiple Choice

Solve using the addition principle. Graph and write set-builder notation for the answer.
- $x+\frac{1}{7}>\frac{4}{7}$ $Solve using the addition principle. Graph and write set-builder notation for the answer. - x+\frac{1}{7}>\frac{4}{7} A) \left\{|x| x>-\frac{3}{7}\right\} B) \left\{|x| x>\frac{3}{7}\right\} C) \left\{\left\{x \mid x<\frac{4}{7}\right\}\right. D) \left\{|x| x>\frac{3}{7}\right\}$

A) $\left\{|x| x>-\frac{3}{7}\right\}$
$Solve using the addition principle. Graph and write set-builder notation for the answer. - x+\frac{1}{7}>\frac{4}{7} A) \left\{|x| x>-\frac{3}{7}\right\} B) \left\{|x| x>\frac{3}{7}\right\} C) \left\{\left\{x \mid x<\frac{4}{7}\right\}\right. D) \left\{|x| x>\frac{3}{7}\right\}$
B) $\left\{|x| x>\frac{3}{7}\right\}$
$Solve using the addition principle. Graph and write set-builder notation for the answer. - x+\frac{1}{7}>\frac{4}{7} A) \left\{|x| x>-\frac{3}{7}\right\} B) \left\{|x| x>\frac{3}{7}\right\} C) \left\{\left\{x \mid x<\frac{4}{7}\right\}\right. D) \left\{|x| x>\frac{3}{7}\right\}$
C) $\left\{\left\{x \mid x<\frac{4}{7}\right\}\right.$
$Solve using the addition principle. Graph and write set-builder notation for the answer. - x+\frac{1}{7}>\frac{4}{7} A) \left\{|x| x>-\frac{3}{7}\right\} B) \left\{|x| x>\frac{3}{7}\right\} C) \left\{\left\{x \mid x<\frac{4}{7}\right\}\right. D) \left\{|x| x>\frac{3}{7}\right\}$
D) $\left\{|x| x>\frac{3}{7}\right\}$
$Solve using the addition principle. Graph and write set-builder notation for the answer. - x+\frac{1}{7}>\frac{4}{7} A) \left\{|x| x>-\frac{3}{7}\right\} B) \left\{|x| x>\frac{3}{7}\right\} C) \left\{\left\{x \mid x<\frac{4}{7}\right\}\right. D) \left\{|x| x>\frac{3}{7}\right\}$

Solve Using the Addition Principle x+17>47x+\frac{1}{7}>\frac{4}{7}x+71​>74​ A) {∣x∣x>−37}\left\{|x| x>-\frac{3}{7}\right\}{∣x∣x>−73​} B) {∣x∣x>37}\left\{|x| x>\frac{3}{7}\right\}{∣x∣x>73​} C) {{x∣x<47}\left\{\left\{x \mid x<\frac{4}{7}\right\}\right.{{x∣x<74​}

Multiple Choice

Correct Answer:VerifiedUnlock this answer nowGet Access to more Verified Answers free of chargeAccess For Free

Solve Using the Addition Principle $x+\frac{1}{7}>\frac{4}{7}$ A) $\left\{|x| x>-\frac{3}{7}\right\}$ B) $\left\{|x| x>\frac{3}{7}\right\}$ C) $\left\{\left\{x \mid x<\frac{4}{7}\right\}\right.$

Correct Answer:
Verified
Unlock this answer now
Get Access to more Verified Answers free of charge