Solve Using the Multiplication Principle$-2 x \frac{1}{14}\right\}\right.$ B)$\left\{x \mid x>\frac{1}{7}\right\}$

The Answer of Solve Using the Multiplication Principle$-2 x \frac{1}{14}\right\}\right.$ B)$\left\{x \mid x>\frac{1}{7}\right\}$

Solve Using the Multiplication Principle$-2 x \frac{1}{14}\right\}\right.$ B)$\left\{x \mid x>\frac{1}{7}\right\}$

The Answer of Solve Using the Multiplication Principle$-2 x \frac{1}{14}\right\}\right.$ B)$\left\{x \mid x>\frac{1}{7}\right\}$

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Solve Using the Multiplication Principle $-2 x<-\frac{1}{7}$ A) $\left\{\left\{|x| x>\frac{1}{14}\right\}\right.$ B) $\left\{x \mid x>\frac{1}{7}\right\}$

Question 240

Multiple Choice

Solve using the multiplication principle.
- $-2 x<-\frac{1}{7}$

A) $\left\{\left\{|x| x>\frac{1}{14}\right\}\right.$
B) $\left\{x \mid x>\frac{1}{7}\right\}$
C) $\left\{x \mid x<-\frac{1}{14}\right\}$
D) $\left\{x \mid x<\frac{1}{7}\right\}$

Solve Using the Multiplication Principle −2x<−17-2 x<-\frac{1}{7}−2x<−71​ A) {{∣x∣x>114}\left\{\left\{|x| x>\frac{1}{14}\right\}\right.{{∣x∣x>141​} B) {x∣x>17}\left\{x \mid x>\frac{1}{7}\right\}{x∣x>71​}

Multiple Choice

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Solve Using the Multiplication Principle $-2 x<-\frac{1}{7}$ A) $\left\{\left\{|x| x>\frac{1}{14}\right\}\right.$ B) $\left\{x \mid x>\frac{1}{7}\right\}$

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